Question

.A 12.0 volt battery is connected to a lamp of resistance of 3.0 ohms. How much energy is transferred to the surroundings by the lamp in 2.0 minutes? (1 Point)

Answer 1

5760joules

Step-by-step explanation:

Energy transferred = QV

Where Q = It

Hence , E = It×V

V = IR

V = 12volts , t = 2mins = 120s, R = 3ohms

12= I × 3

I = 12/3

I = 4amps

E = 4×120×12

E = 5760joules

Hence energy transferred is 5760joules