Question

A bag contains 7 red marbles, 3 blue marbles and 5 green marbles. If three marbles

are drawn out of the bag, what is the probability, to the nearest 10th of a percent, that
all three marbles drawn will be green?

Answer 1

2.2

Explanation:

5/15 x 4/14 x 3/13

Answer 2

3.7%

Explanation:

We know that from this situation, the probability of drawing a single green marble is 1/3. However, to find the probability of drawing 3 green marbles, we will need to do:

`P= (1)/(3)* (1)/(3)*(1)/(3)`

We get a probability of:

`P= (1)/(27)`

This converts to a percentage of:

`(1)/(27)= 0.037 \\ 0.037*100= 3.7%`

We get a percentage of 3.7%