A. How many moles are in 4.5 kg (4,500g) of Ca(OH)2?

asked Sep 27, 2021 230k views

3 votes

by Moia

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5 votes

Answer:

61 moles Ca(OH)2

Step-by-step explanation:

$\frac{4500 g Ca(OH)2}{}$ *
(1 moleCa(OH)2)/(74.093 g Ca(OH)2) =
(4500)/(74.093) = 61 moles Ca(OH)2

Svz answered Oct 4, 2021