Question

A uniform meter stick (with a length of 1.00 meter) has a mass of 108 g. It is supported at its midpoint by a vertical rigid blue rod (the two are connected by a frictionless hinge). A weight (mass 1) has a mass of 21g and it hangs from a (massless) string at a distance of 24 cm from the left end of the stick. Another weight (mass 2) has a mass of 27 g and it hangs from a string at a distance of 91 cm from the left end of the stick. The system was held motionless by the (vertical) blue rod and by a vertical red string at the right end of the stick (one meter from the left end of the stick). Red string Then somebody cut the red string. The blue rod still holds the center of the stick in place but the system can now rotate about the midpoint of the stick Immediately after the red string is cut.

Find the vertical tension in the blue rod.
1. 508 N
2. 143 N
3.153 N
4. 0.4704N
5. 0.7644N
6. 1.539 N

Answer 1

Answer:4

Step-by-step explanation:

Given

`m_1=21\ gm`

`m_2=27\ gm`

Mass of stick is
`m=108\ gm`

Let T be the tension in the red string

Now if the red string is cut , suppose T is the tension in the blue rod immediately after cut

Therefore

`T=m_1g+m_2g`

`T=(0.021+0.027)* 10`

`T=0.48\ N`