Answer:
Check the explanation
Explanation:
Following is the completed table with p values:
Predictor Coef SE coef T P-value
Constant 16.301 6.015 16.301/6.015=2.710 0.01785
Distance 3.554 1.663 3.554/1.663=2.137 0.05218
Here degree of freedom will be dof=15-2=13
Since p-value of distance is greater than 0.05 so distance is not significant to the model.
B. There is suggestive, but weak evidence to indicate that the distance a from the nearest fire station is a significant predictor of the amount of damage (t-statisticequals=2.137, dofequals=13,P-valueequals=0.052).