30.5k views
4 votes
Find three consecutive interferes whose sum is 96

User Cguenther
by
8.0k points

1 Answer

7 votes

Answer:

31, 32, 33

Explanation:

x + x + 1 +x + 2 = 96

3x + 3 = 96

-3 -3

3x = 93

/3 /3

x = 31

31 is the first number, so since they’re consecutive, the second two numbers are 32 and 33.

User Gautam Singh
by
7.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.