Question

A right triangle has side lengths 9, 40, and 41 as shown below.

B
40
Use these lengths to find cosB, tanB, and sin B.
9

Answer 1

COS B= 9/41
tan B= 40/9
sin B= 40/41

Answer 2

cos B = 9/41

tan B = 40/9

sin B = 40/41

Explanation:

There is no picture, so I am making a few assumptions.

I am assuming that angle C is the right angle and is opposite 41.

I am also assuming that angle B is formed by the sides that measure 9 and 41. The hypotenuse is 41.

For angle B, the adjacent leg is 9, and the opposite leg is 40.

cos B = adj/hyp = 9/41

tan B = opp/adj = 40/9

sin B = opp/hyp = 40/41