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Which equation is the inverse of y = 2x^2 - 8?

Y=+sqr rt x+8/2
Y=+sqr rt x+8/2
Y=+sqr rt x/2+8
Y=+sqr rt x/2+4
ASAP

Which equation is the inverse of y = 2x^2 - 8? Y=+sqr rt x+8/2 Y=+sqr rt x+8/2 Y=+sqr-example-1

1 Answer

3 votes

Answer: A

Explanation:


y=2x^2-8

1. Swap x and y.


x=2y^2-8

2. Solve for the new y.

Add 8


x+8=2y^2

Divide by 2.


(x+8)/(2)=y^2

Extract the square root.


\sqrt{(x+8)/(2) }=y

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