Answer:
Average complaint rate = total number of defects/(no of samples*sample size) = 12/(12*10) = 0.1 = p-bar
Sp = sqrt((p-bar*(1-p-bar))/sample size) = sqrt((0.1*(1-0.1))/10) = 0.09486833
UCL = p-bar + z*Sp = 0.1+3*0.09486833 [for 99.73% confidence level, z = 3] = 0.38460499
LCL = p-bar - z*Sp = 0.1-3*0.09486833 = -0.18460499 = 0 (Adjusted)
yes the enrollment appears to be in control