Question

Jack just completed the program for the Flesch text analysis from this chapter’s case study. His supervisor, Jill, has discovered an error in his code. The error causes the program to count a syllable containing consecutive vowels as multiple syllables. Suggest a solution to this problem in Jack’s code and modify the program so that it handles these cases correctly.

An example text and the program input and output is shown below:
example.txt
Or to take arms against a sea of troubles, And by opposing end them? To die: to sleep.
Enter the file name: example.txt
The Flesch Index is 102.045
The Grade Level Equivalent is 1
3 sentences
18 words
21 syllables
"""
Program: textanalysis.py
Author: Ken
Computes and displays the Flesch Index and the Grade
Level Equivalent for the readability of a text file.
"""

# Take the inputs
fileName = input("Enter the file name: ")
inputFile = open(fileName, 'r')
text = inputFile.read()

# Count the sentences
sentences = text.count('.') + text.count('?') + \
text.count(':') + text.count(';') + \
text.count('!')

# Count the words
words = len(text.split())

# Count the syllables
syllables = 0
vowels = "aeiouAEIOU"
for word in text.split():
for vowel in vowels:
syllables += word.count(vowel)
for ending in ['es', 'ed', 'e']:
if word.endswith(ending):
syllables -= 1
if word.endswith('le'):
syllables += 1

# Compute the Flesch Index and Grade Level
index = 206.835 - 1.015 * (words / sentences) - \
84.6 * (syllables / words)
level = int(round(0.39 * (words / sentences) + 11.8 * \
(syllables / words) - 15.59))

# Output the results
print("The Flesch Index is", index)
print("The Grade Level Equivalent is", level)
print(sentences, "sentences")
print(words, "words")
print(syllables, "syllables")

The given code needs to be edited to be correct.

Answer 1

Check the explanation

Step-by-step explanation:

CODE;

# Take the inputs.

fileName = input("Enter the file name: ")

inputFile = open(fileName, 'r')

text = inputFile.read()

# Count the sentences

sentences = text.count('.') + text.count('?') + \

text.count(':') + text.count(';') + \

text.count('!')

# Count the words

words = len(text.split())

# Count the syllables

syllables = 0

vowels = 'aeiouAEIOU'

for word in text.split():

if word[0] in vowels:

syllables += 1

for index in range(1, len(word)):

if word[index] in vowels and word[index - 1] not in vowels:

syllables += 1

for ending in ['es', 'ed', 'e']:

if word.endswith(ending):

syllables -= 1

if word.endswith('le'):

syllables += 1

# Compute the Flesh index and grade level

index = 206.835 - 1.015 * (words / sentences) - \

84.6 * (syllables / words)

level = int(round(0.39 * (words / sentences) + 11.8 * \

(syllables / words) - 15.59))

# Output the results

print("The Flesch Index is", index)

print("The Grade Level Equivalent is", level)

print(sentences, "sentences")

print(words, "words")

print(syllables, "syllables")

====================================================

Kindly check the attached image below for the code screenshot and output.