Question

please answer quickly..... how to calculate the density of the oil, here is the question ; The diagram shows the use of a U-tube manometer to compare the densities of two liquids . If h1= 10.0cm and h2= 20.0cm. Calculate the density of the oil given that the density of water is 1.0 g cm3.

Answer 1

Rho{oil} = 0.50 g/cm³

Step-by-step explanation:

Given is Rho{water} = 1.0 g/cm³

By the way, this is the same as 1.0 *10³ kg/m³

Sometimes you need to make sure to use the same units, meaning all in cm and g or all in m and in kg. This is not important here but the outcome will be in g/cm³ and not in kg/m³

There is equilibrium, so there fore:

Rho{oil}*g*h2 = Rho{water}*g*h1

Divide both sides of the = sign by g:

Rho{oil}*h2 = Rho{water}*h1

Rho{oil} = (Rho{water}* h1)/ h2

fill the numbers

Rho{oil} = (1 * 10)/ 20

Rho{oil} = 0.50 g/cm³