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If ln(x^2-x-1)=0 , then x= ?

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Answer:

x = -1 or 2

Explanation:

Taking the antilog, you have the quadratic ...

x^2 -x -1 = 1

x^2 -x -2 = 0 . . . . subtract 1

(x -2)(x +1) = 0 . . . factor

The values of x that make these factors zero are the solutions to the equation.

x = 2 or x = -1

If ln(x^2-x-1)=0 , then x= ?-example-1
User Littlejon
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