Question

Nylon 6,6 may be formed by means of a condensation polymerization reaction in which hexamethylene diamine [NH2-(CH2)6-NH2] and adipic acid react with one another with the formation of water as a byproduct. What masses of (a) hexamethylene diamine and (b) adipic acid are necessary to yield 36 kg of completely linear nylon 6,6? This polymerization reaction occurs according to the following equation:

Answer 1

Step-by-step explanation:

molecular mass of nylon ( C₁₂H₂₂N₂O₂ ) = 226 gm

Molecular mass of adipic acid = 146 gm

Molecular mass of hexamethylenediamine = 116 gm

no of moles of nylon = 36000 / 226

= 159.29

one mole of nylon requires one mole of hexamethylenediamine and one

mole of adipic acid .

159.29 mole of nylon requires 159.29 mole of hexamethylenediamine and 159.29 mole of adipic acid

159.29 mole of hexamethylenediamine

= 159.29 x 116 gm

= 18.48 kg of hexamethylenediamine

159.29 mole of adipic acid = 159.29 x 146 gm

= 23.26 kg .

18.48 kg of hexamethylenediamine and 23.26 kg of adipic acid will be required.