Question

the singh and robinson families planned a trip to busch gardens. they needed to buy one ticket per person and then pay for parking. the singh's spent $335 for 5 people and the robinsons spent $ 465 for 7 people. how much did each ticket cost? How much was parking

Answer 1

Let x represent cost of each ticket and y represent cost of parking.

We have been given that the Singh's spent $335 for 5 people and parking. We can represent this information in an equation as:

`5x+y=335...(1)`

We are also told that the Robinson spent $465 for 7 people and parking. We can represent this information in an equation as:

`7x+y=465...(2)`

Now we will use elimination method to solve our given system of equations.

Upon subtracting equation (1) from equation (2), we will get:

`7x-5x+y-y=465-335`

`2x=130`

`(2x)/(2)=(130)/(2)`

`x=65`

Therefore, the each ticket costs $65.

Upon substituting
`x=65` in equation (1), we will get:

`5(65)+y=335`

`325+y=335`

`325-325+y=335-325`

`y=10`

Therefore, the parking costs $10.