Consider the quadratic function 8x2=-7x+6 what is the constant of the function

Question

asked Apr 27, 2021 23.0k views

1 Answer

DragonCherry · Answer 1 · 2021-05-03T04:44:42+0000

Answer:

6

Explanation:

This quadratic needs to be in standard form.

$f(x) = a {x}^(2) + bx + c$

$8 {x}^(2) = - 7x + 6$

Subtract
$8 {x}^(2)$ from both sides of the equation.

$8 {x}^(2) - 8 {x}^(2) = - 8 {x}^(2) - 7x + 6$

$- 8 {x}^(2) - 7x + 6$

The constant is the value that stays "constant" or doesn't have a variable. In quadratics in standard form, the constant is the
value.

a = - 8

b = - 7

c = 6

Since the
value is 6, the constant is equal to 6