65.5k views
4 votes
What is the first step in writing f(x) = 6x2 + 5 - 42x in vertex form?

User Schnill
by
4.9k points

2 Answers

1 vote

Answer:

Back to seeks out of the first two times

Explanation:

User Tsuki
by
5.3k points
5 votes

The first step in writing f(x) = 6x^2 + 5 - 42x in vertex form is to put it into proper quadratic form and then finding the axis of symmetry. Proper quadratic form is ax^2 + bx + c. The formula to find the axis of symmetry is -b over 2a.

User Pree
by
5.1k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.