Question

Calculate the pH of the solution:

[OH-] = 1 x 10^-11M


a

12.0

b

2.7

c

3.0

d

11.0

Answer 1

c. 3.0

Step-by-step explanation:

pOH = -log[OH-]

pOH = -log[1 x 10^-11 M

pOH = 11

pH + pOH = 14

pH + 11 = 14

pH = 14 - 11

pH = 3

c. 3.0