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What is the value of the discriminant, b2 − 4ac, for the quadratic equation 0 = x2 − 4x + 5, and what does it mean about the number of real solutions the equation has?

User CTZStef
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1 Answer

3 votes

We have been given an equation
0 = x^2-4x + 5. We are asked to find the discriminant of our given equation.

We will use discriminant formula to solve our given problem.


D=b^2-4ac, where,

D = Discriminant,

b = Coefficient of x term,

a = Coefficient of
x^2 term,

c = Constant.


D=(-4)^2-4(1)(5)


D=16-20


D=-4

When D is less than 0, then equation has no real solutions.

When D is equal to 0, then equation one real solution.

When D is greater than 0, then equation has two real solutions.

Since
-4 is less than 0, therefore, our given equation has no real solutions.

User Snug
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8.3k points
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