Question

Solve this quadratic equation.
x2 + 5x + 3 = 0

Answer 1

The answer is actually
`x = (-5+√(13) )/(2)` or
`x = \frac{-5 -√(13) }{\ {2} }`

Explanation:

We have the given equation:

`x^(2) + 5x + 3=0`

• We have to use the quadratic formula in order to solve.

`x = \frac{-b +or-\sqrt{b^(2)- 4ac } }{2a}`

+ or - in this formula stands for the symbol ±

• Given this formula:

`x^2 + 5x + 3 = 0`

a = 1

b = 5

c = 3

• Plug it in:

`x = \frac{-5+or-\sqrt{5^(2)-4(1)(3) } }{2(1)} \\\\x = (-5+or-√(25-12) )/(2) \\`

Solution:

`x = (-5+or-√(13) )/(2)`

This is as far as it can be simplified.

Answer 2

Explanation:

2x+5x+3=0

7x+3=0

-3 -3

=0 =-3

7x=-3

-3/7=-0.42857142857

x=-0.42857142857

I think it is right