138k views
0 votes
Solve this quadratic equation.
x2 + 5x + 3 = 0

User Pba
by
8.6k points

2 Answers

3 votes

Answer:

The answer is actually
x = (-5+√(13) )/(2) or
x = \frac{-5 -√(13) }{\ {2} }

Explanation:

We have the given equation:


x^(2) + 5x + 3=0

  • We have to use the quadratic formula in order to solve.


x = \frac{-b +or-\sqrt{b^(2)- 4ac } }{2a}

+ or - in this formula stands for the symbol ±

  • Given this formula:


x^2 + 5x + 3 = 0

a = 1

b = 5

c = 3

  • Plug it in:


x = \frac{-5+or-\sqrt{5^(2)-4(1)(3) } }{2(1)} \\\\x = (-5+or-√(25-12) )/(2) \\

Solution:


x = (-5+or-√(13) )/(2)

This is as far as it can be simplified.

User Alivia
by
8.5k points
7 votes

Answer:

Explanation:

2x+5x+3=0

7x+3=0

-3 -3

=0 =-3

7x=-3

-3/7=-0.42857142857

x=-0.42857142857

I think it is right

User Okeisha
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories