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A drawer of loose socks contains 2 red socks, 2 green socks, and 6 white socks. Which best describes how to determine the probability of pulling out a white sock, not replacing it, and pulling out another white sock?
The probability that the first sock is white is (StartFraction 6 over 10 EndFraction) and that the second sock is white is (StartFraction 6 over 10 EndFraction), so the probability of choosing a pair of white socks is StartFraction 36 over 100 EndFraction = StartFraction 18 over 50 EndFraction.
The probability that the first sock is white is (StartFraction 1 over 10 EndFraction) and that the second sock is white is (StartFraction 1 over 10 EndFraction), so the probability of choosing a pair of white socks is StartFraction 1 over 100 EndFraction.
The probability that the first sock is white is (StartFraction 6 over 10 EndFraction) and that the second sock is white is (StartFraction 5 over 9 EndFraction), so the probability of choosing a pair of white socks is StartFraction 30 over 90 EndFraction = one-third.
The probability that the first sock is white is (StartFraction 1 over 10 EndFraction) and that the second sock is white is (StartFraction 1 over 9 EndFraction), so the probability of choosing a pair of white socks is StartFraction 1 over 90 EndFraction.

2 Answers

7 votes

Answer:

Its C checked it on edgunity

Explanation:

User PulledBull
by
5.6k points
5 votes

Answer:

Probability of pulling out a white sock = 6/10.

Probability of pulling out another white sock = 5/9.

Explanation:

User Iteles
by
6.4k points