Question

What is the molarity of a KF(aq) solution containing 3.0 mol of KF in 2.00L of solution?

Answer 1

Answer : The molarity of
`KF` in the solution is 1.5 M.

Explanation : Given,

Moles of
`KF` = 3.0 mol

Volume of solution = 2.00 L

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

`\text{Molarity}=\frac{\text{Moles of }KF}{\text{Volume of solution (in L)}}`

Now put all the given values in this formula, we get:

`\text{Molarity}=(3.0mol)/(2.00L)=1.5mole/L=1.5M`

Therefore, the molarity of
`KF` in the solution is 1.5 M.