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In the following reaction 6.13g of water (H₂O) is produced the theoretical yield of water (H₂O) is 8.17g, what is the percent yield of water? *

1 Answer

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Answer:

Percentage yield = 75.03%

Step-by-step explanation:

Actual yield = 6.13

Theoretical yield = 8.17g

Percentage yield = ?

Percentage yield of compound in a reaction is the percentage ratio of actual yield to theoretical yield of that compound

Percentage yield = (actual yield / theoretical yield) * 100

Percentage yield = (6.13/8.17) * 100

Percentage yield = 0.7503 * 100

Percentage yield = 75.03%

Percentage yield of water in the reaction is 75.03%

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