Answer:
Check the explanation
Explanation:
Hypotheses are:
![H_(0):\mu_(1)=\mu_(2),H_(1):\mu_(1)\\eq \mu_(2)](https://img.qammunity.org/2021/formulas/mathematics/college/x9sasdigmrpzn473e7pumdchqpshzubvuh.png)
Following is the output of t test:
Hypothesis Test: Independent Groups (t-test, pooled variance)
X1 X2
12 15.5 mean
3.6591 3.6839 std. dev.
10 15 n
23 df
-3.5000 difference (X1 - X2)
13.4999 pooled variance
3.6742 pooled std. dev.
1.5000 standard error of difference
0 hypothesized difference
-2.33 t
.0287 p-value (two-tailed)
The p-value is:
p-value = 0.0287
Since p-value is less than 0.05 so we reject the null hypothesis. That is we can conclude that the exercise program have a significant effect.
(b)
The cohen's d is
![d=\left |\frac{\bar{x}_(1)-\bar{x}_(2)}{s_(p)} \right |=\left |(12-15.5)/(3.6742 ) \right |=0.95](https://img.qammunity.org/2021/formulas/mathematics/college/bvac7bjrax70m92zhi8r3c2qnlyqiqg6ww.png)