82,991 views
8 votes
8 votes
Find the 2 consecutive integers whose squares have a difference of 239

User Iddo
by
2.7k points

1 Answer

24 votes
24 votes

Answer:

119 and 120

Explanation:

let the consecutive integers be n and n + 1 , then

(n + 1)² - n² = 239

n² + 2n + 1 - n² = 239

2n + 1 = 239 ( subtract 1 from both sides )

2n = 238 ( divide both sides by 2 )

n = 119

n + 1 = 119 + 1 = 120

the 2 integers are 119 and 120

as a check

120² - 119² = 14400 - 14161 = 239

User Dtothefp
by
3.2k points