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(3x^2−12x)(x^2−2x+1) factor completely
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(3x^2−12x)(x^2−2x+1) factor completely

User Toman
by
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1 Answer

6 votes

Answer:

3x(x - 4)(x - 1)²

Explanation:

(3x^2−12x)(x^2−2x+1)

[3x² - 12x][x² - 2x + 1]

[3x(x - 4)] × [x² - 2(x)(1) + 1²]

3x(x - 4)(x - 1)²

User Jianpx
by
4.7k points
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