Question

How many grams of perchloric acid should be dissolved in 8500mL of water to make a solution with pH 3.3

Answer 1

0.427 g HClO4

Step-by-step explanation:

[H+]= 10^-3.3 = 5.01 x 10^-4 M

8500 mL=8.5 L

M= mol solute/ L solution

mol solute= M* L solution

mol solute= (5.01 x 10^-4 M * 8.5 L)

mol solute= 4.26 x 10^3 mol HClO4

1 mol HClO4 -> 100. 4 g

4.26 x 10^3 mol HClO4 -> x

x=0.427 g HClO4