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Sin(2x) - 3cos x = 0
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Sin(2x) - 3cos x = 0

User B Chen
by
3.3k points

2 Answers

0 votes

Answer:sin(inverse)(3/2)

Explanation:

sin(2x)-3cosx=0 sin2x=2sinxcosx

2sinxcosx-3cosx=0

2sinxcosx=3cosx

Divide both sides by cosx

2sinxcosx ➗ cosx =3cosx ➗ cosx

2sinx=3

Divide both sides by 2

2sinx ➗ 2=3 ➗ 2

sinx=3/2

x=sin(inverse)(3/2)

User Sasikanth
by
3.6k points
6 votes

Answer:

2π3,(4π3)

Explanation:

User Lukaszrys
by
3.3k points
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