Question

If 25.0 moles of gasohol (C2H60) burns this way, how many moles of oxygen are

needed?
C2H60 + 3 O2 --> 2 CO2 + 3 H20
a) 75.0 moles
b) 37.5 moles
c) 16.7 moles
d) 8.3 moles

Answer 1

a. 75 mol O2

Step-by-step explanation:

1 mol C2H6O -> 3 mol O2

25 mol C2H6O -> x

x= (25 mol C2H6O * 3 mol O2)/ 1 mol C2H6O

x= 75 mol O2