Answer:
Although strictly speaking of mathematics i.e. theoritically,
t
can take any value from
{ − ∞ , ∞ ] ,
however, it is essentially a physical problem related to Physics and we cannot have negative
t i.e. t ≥ 0
Further, after the maximum is reached at t = 2 (observe that first differential is h ' ( t ) = − 32 t + 64 , which is zero at t = 2 and second derivative h ' ' ( t ) = − 32 is negative and at this we have h ( 2 ) = 64 ), at t = 4 , h ( 4 ) = 0 i.e. toy rocket falls back to the ground and as such, we cannot have h > 4 .
Hence, domain for t is [ 0 , 4 ] .
tbh google