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How many moles of AgCl2 are in 5.78x1024 molecules of AgCl2?

a) 3.48x1048 moles AgCl2
b) 1375.87 moles AgCl2
c) 0.07 moles AgCl2
d) 9.60 moles AgCl2

User Jemell
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1 Answer

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Answer:

9.6 mol AgCl2

Step-by-step explanation:

You have to use Avogadro's number: 6.023 x 10^23

5.78 x 10^24 molecules (1 mol AgCl2/ 6.023 x 10^23 molecules) =9.6 mol AgCl2

User Rosencreuz
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