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(x−5)^2+n=0
what is n?

1 Answer

3 votes

Answer:

not sure, but I got n = 25-x ^2

Explanation:

1. distribute the squared to each term in the parenthesis

2. x^2-25+n=0

3. Ad 25 to both sides of the equation

4. subtract x from both sides

you get: n=25-x^2 OR n=-x^2+25

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