Question

`-8x^2√(180) + 9x√(5x^2)`

Answer 1

`-39x^(2) √(5)`

Explanation:

Firstly, you have to know these:

`a√(x) + b√(x) = (a+b)√(x) \\\sqrt{a.b^(2) } =b√(a) \\ c\sqrt{a.b^(2) } =(c.b)√(a) \\a√(x) - b√(x) = (a-b)√(x)`

About your question :

`√(180) = \sqrt{6^(2).5} = 6√(5)`

`-8x^(2) . 6√(5) = -48x^(2)√(5)`

`\sqrt{5x^(2)} = x√(5)`

`9x\sqrt{5x^(2)} = 9x.x√(5) = 9x^(2) √(5)`

-48x²√5 + 9x²√5 = -39√5

Hope this helps ^-^