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The pressure observed after reaction with Zn metal and HCl should be corrected to subtract the pressure due to water vapor present at the final system temperature (22°C). Write down the corrected pressure P:________

User Djuarezg
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2 Answers

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Final answer:

The corrected pressure P after reacting Zn with HCl is obtained by subtracting the vapor pressure of water at 22°C (19.84 torr) from the total observed pressure using Dalton's law of partial pressures.

Step-by-step explanation:

To find the corrected pressure P after reacting zinc (Zn) metal with hydrochloric acid (HCl), you must subtract the pressure due to water vapor from the observed pressure. At 22°C, the vapor pressure of water is given as 19.84 torr. Using Dalton's law of partial pressures, the corrected pressure P can be calculated using the equation Pg= PTotal - PH2O, where Pg is the pressure of the gas collected, PTotal is the total observed pressure, and PH2O is the pressure of water vapor.

User Tjgragg
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4 votes

Answer:

The correct answer to the following question will be "Pressure = 18394.168 torr".

Step-by-step explanation:

The reaction is:

Zn + 2HCl ⇒ ZnCl2 + H2

Let,

H2 = 1 mole

Volume, V = 1 L

As we know,


Pressure(P) = (nRT)/(V)

On putting the values in the above formula, we get


P=(1* 0.0821* 295.15)/(1)


P=24.2318 \ atm


P=24.2318* 760


P=18416.168 \ torr

Now,


P \ original = P \ obtained-PH2O


P \ original=18416.168-22


P \ original=18394.168 \ torr

User Carlos Irano
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