20.8k views
1 vote
What is the perimeter of the rectangle whose area =x^2+3x-40?

User Jim Bolla
by
8.6k points

1 Answer

6 votes

Answer:

Perimeter = 4x + 6

Explanation:

The area of a rectangle is given by:

Area = L * W

Where L is the length and W is the width.

In this case, we need to factorate the area to find L and W:

Area = x^2+3x-40

Making Area = (x + a)*(x + b), we have:

a * b = -40

a + b = 3

Solving this system, we have a = 8 and b = -5

So we have Area = (x + 8)*(x - 5)

So Length = x+8 and Width = x-5

Perimeter = 2*L + 2*W = 2x + 16 + 2x - 10 = 4x + 6

User Goul
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories