Question

Determine angle B by using the law of sines. Please help, thank you!

Answer 1

sin 110/25=sin B/16
sin Bx25=16xsin 110
B= sin inverse(16xsin 110/25)
B=37.0 degrees.

Answer 2

B=36.97

Explanation:

non-right triangle

c/sin C = b/ sin B

`(25)/(sin(110)) =(16)/(sinB)`

cross multiply to isolate sinB

25sinB=16sin(110)

divide by 25 and isolate angle B by arccos or sin^-1

B=sin^1 (
`(16sin(110))/(25)`)

B= 36.97