Question

Calculate the number of molecules in 22.4L of CH4 gas at STP​

Answer 1

Answer:
`6.023* 10^(23)` molecules

Step-by-step explanation:

According to ideal gas equation:

`PV=nRT`

P = pressure of gas = 1 atm (at STP)

V = Volume of gas = 22.4 L

n = number of moles = ?

R = gas constant =
`0.0821Latm/Kmol`

T =temperature =
`273K` (at STP)

`n=(PV)/(RT)`

`n=(1atm* 22.4L)/(0.0821L atm/K mol* 273K)=1mole`

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number
`6.023* 10^(23)` of particles.

1 mole of
`CH_4` contains
`6.023* 10^(23)` molecules