Question

What is the value of the charge that experiences a force of 2.4x10^-3N in an electric field of 6.8x10^-5 N/C

Answer 1

Answer:35.3C

Step-by-step explanation:

Force=2.4 x 10^(-3)N

Electric field intensity=6.8 x 10^(-5)N/C

charge=force ➗ electric field intensity

Charge=(2.4x10^(-3)) ➗ (6.8x10^(-5))

Charge=35.3C

Answer 2

plug it into your calculator

Step-by-step explanation:

F= q E

↓↓↓↓

q = F/E

(F = 2.4....)

(E = 6 8....)