Question

6) How many grams of hydrogen can be produced if 50.0 grams of magnesium is reacted

with 75.0 grams of hydrochloric acid?
7) Identify the LIMITING reactant.
8) How much of the LIMITING reactant is left over after the reaction stops?
9) How much of the EXCESS reactant is used up in the reaction?
10) How much of the EXCESS reactant is left over when the reaction stops?
*Write and balance the following equation

Answer 1

The balanced chemical equation would be as follows:

Mg + O2 → MgO2

We are given the amounts of the reactants. We need to determine first which one is the limiting reactant. We do as follows:

62.0 g Mg (1 mol / 24.31 g ) = 2.55 mol Mg

55.5 g O2 ( 1 mol / 32 g ) = 1.74 mol O2 -----> consumed completely and therefore the limiting reactant

2.55 mol - 1.74 mol O2( 1 mol Mg / 1 mol O2 ) = 0.81 mol Mg excess

Step-by-step explanation: