Question

slader An experiment is carried out where 13.9 g of solid NaOH is dissolved in 250.0 g of water in a coffee-cup calorimeter. Dissolution is not a chemical reaction, but is a chemical process: NaOH(s) → Na+(aq) + OH-(aq) The mixture can be assumed to have the same specific heat capacity as liquid water (4.18 J g-1 ºC-1). What is the mass of the surroundings where the temperature is being measured in the experiment?

Answer 1

The mass of the surrounding is
`M_t = 263.9 \ g`

Step-by-step explanation:

From the question we are told that

The mass of
`NaOH` is
`m = 13.9 \ g`

The mass of water is
`m_w = 250.0g`

The chemical equation for the dissociation process is

`NaOH _((s) ) ---> Na^(+)_((aq)) + OH^(-) _((aq))`

The specific heat capacity of the mixture is
`c_p = 4.18 J g^(-1) C^(-1)`

The combined mass of the solution is

`M_t = 13 + 250`

`M_t = 263.9 \ g`

The mass of the surround here is the mass of the coffee-cup calorimeter and this contain the mixture ( water and the NaOH ) so the mass of the surrounding is

`M_t = 263.9 \ g`