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25 votes
Line p goes through the origin and contains the point (-2,-5). Which

equation represents line p?

User Insoo
by
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1 Answer

10 votes


\stackrel{origin}{(\stackrel{x_1}{0}~,~\stackrel{y_1}{0})}\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-5}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-5}-\stackrel{y1}{0}}}{\underset{run} {\underset{x_2}{-2}-\underset{x_1}{0}}}\implies \cfrac{-5}{-2}\implies \cfrac{5}{2}


\begin{array}c \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{\cfrac{5}{2}}(x-\stackrel{x_1}{0})\implies y=\cfrac{5}{2}x

User Dreanmer
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