Answer:
We conclude that % of adults who say that it is morally wrong to not report all income on tax returns is different from 75%.
Explanation:
We are given that in a recent poll of 750 randomly selected adults, 589 said that it is morally wrong to not report all income on tax returns.
We have to test the claim that 75% of adults say that it is morally wrong to not report all income on tax returns.
Let p = % of adults who say that it is morally wrong to not report all income on tax returns.
So, Null Hypothesis,
: p = 75% {means that % of adults who say that it is morally wrong to not report all income on tax returns is 75%}
Alternate Hypothesis,
: p
20% {means that % of adults who say that it is morally wrong to not report all income on tax returns is different from 75%}
The test statistics that would be used here One-sample z proportion statistics;
T.S. =
~ N(0,1)
where,
= sample proportion of adults who said that it is morally wrong to not report all income on tax returns =
= 0.785
n = sample of adults = 750
So, test statistics =

= 2.33
The value of z test statistics is 2.33.
Now, P-value of the test statistics is given by the following formula;
P-value = P(Z > 2.33) = 1 - P(Z
2.33)
= 1 - 0.9901 = 0.0099
Also, P-value for two-tailed test is calculated as = 2
0.0099 = 0.0198
Since, the P-value of test statistics is less than the level of significance as 0.0198 < 0.05, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.
Therefore, we conclude that % of adults who say that it is morally wrong to not report all income on tax returns is different from 75%.