Question

The initial and final velocities of two blocks experiencing constant acceleration are respectively −7.45 m/s and 14.9 m/s. (a) The first object has displacement 22.5 m. Find its acceleration (in m/s2). (Indicate the direction with the sign of your answer.) 1 3.7 Correct: Your answer is correct. m/s2 (b) The second object travels a total distance of 22.6 m. Find its acceleration (in m/s2). (Indicate the direction with the sign of your answ

Answer 1

a)
`a_(1)=3.7 m/s^(2)`

b)
`a_(2)=3.68 m/s^(2)`

Step-by-step explanation:

a) The displacement of the first object is 22.5 m, so we can use the next equation:

`v_(f)^(2)=v_(i)^(2)+2a\Delta x`

`a=(v_(f)^(2)-v_(i)^(2))/(2x)`

`a=(14.9^(2)-(-7.45)^(2))/(2*22.5)`

`a_(1)=3.7 m/s^(2)`

positive acceleration.

b) Using the same equation we can find the second value of the acceleration:

`a=(v_(f)^(2)-v_(i)^(2))/(2x)`

`a=(14.9^(2)-(-7.45)^(2))/(2*22.6)`

`a_(2)=3.68 m/s^(2)`

positive acceleration.

I hope it helps you!