Question

Write an equation in slope-intercept form for the line perpendicular to y = &v - 9 that passes through the point

(9,-9).
a.y=8x- 81
c. y=8x- 9
b. y=-1/8x-63/8
d. y = -1/8x+585/8

Answer 1

The equation of the line perpendicular to y = -v - 9 that passes through the point (9, -9) is y = -x.

Step-by-step explanation:

To find the equation of a line perpendicular to a given line, we need to determine the negative reciprocal of the slope of the given line. The given line is y = -v - 9, so the slope is -1.

Since the line passes through the point (9, -9), we can substitute the coordinates into the equation y = mx + b to solve for b. Substitute 9 for x and -9 for y:

-9 = -1(9) + b

-9 = -9 + b

b = 0

Therefore, the equation of the line perpendicular to y = -v - 9 that passes through the point (9, -9) is y = -1x + 0, which simplifies to y = -x. The correct answer is option d. y = -1/8x + 585/8.