Question

In the equation, f(x) = 6x²+ 8x which value(s) for x make f(x) = 0 true?​

Answer 1

0 & -4/3.

Explanation:

If f(x)=0, then 6x^2 + 8x=0. Next, factoring out an x, we get x(6x+8)=0. So either x=0 or 6x+8=0. In our second equation, x=-4/3.