Question

To make a gallon of sweet tea you have to heat the water to 100.00 °C. If the pot on

the stove contains 57.2 grams of water, and the temperature at the tap is 22.7 °C,
how much heat must be absorbed by the water?

Answer 1

Q = 18.49kJ

Step-by-step explanation:

Mass = 57.2g

T₁ = 22.7°C

T2 = 100°C

Specific heat capacity of water = 4.184J/g°C

Heat energy (Q) = ?

Q = MC∇T

Q = MC(T₂ - T₁)

Q = 57.2 * 4.184 (100 - 22.7)

Q = 57.2 * 4.184 * 77.3

Q = 18499.80J

Q = 18.49kJ