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5 votes
Condense log5 (2y) + log5 (8)

User Skyronic
by
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1 Answer

2 votes

Apply log rule [
\text{log}_a(xy)=\text{log}_ax+\text{log}_ay ] to condense.


\text{log}_5(2y)+\text{log}_5(8)=\text{log}_5(2y*8)


\text{log}_5(16y)

Best of Luck!

User Jonnow
by
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