Question

Four circles, each with a radius of 2 inches, are removed

from a square. What is the remaining area of the square?
O
O
0
O
(16 – 41Pi) in.?
(16 – Pi) in.?
(64 – 16pi) in.2
(64 – 41Pi) in.2

Answer 1

64 - 16pi

Explanation:

Since 4 circles are circumscribed by a square, then the side length of the square is 8

The area of the square is 8^2 = 64

The area of 4 squares is 4 * pi*2^2 = 16pi

Answer is 64 - 16pi