Answer:
a) T(t)= 100e^(-0.0513t)
b) See attachment for graph
y-intercept is inital temperature
domain is t≥0, range is 0 <T≤100
c) 44.9min
Explanation:
a) at t=0, T=100
at t=1, T=95
T(t)= Ae^-kt
100=Ae^(-k×0)
A=100
95=100e^(-k
k=0.0513
T(t)= 100e^(-0.0513t)
b) as time reaches infinity, temperature of pudding becomes approximately equal to 0. x-axis is the asyptote of the graph
c) 10= 100e^(-0.0513t)
t= 44.9 min