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What is the maximum area that can be completed with 240 feet of fencing? What are the dimensions of this playground. Answer in complete sentences.

User AmrAngry
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1 Answer

7 votes

Answer:

The dimension of the playground is 60ft by 60ft and the maximum area of the playground is 3,600ft²

Explanation:

Given

A playground of 240 feet of fencing.

Required.

Dimension of the playground.

Before solving any further, it'll be assumed that the playground is a rectangular shape.

Having said this,

If the playground required 240ft of fencing, then it's perimeter is 240ft.

The perimeter of a Rectangle is;

P = 2(L + W)

Where P represents the perimeter;

L and W represent the length and the width of the rectangle respectively.

By substituting 240 for P, we have

240 = 2(L + W)

Multiply both sides by ½

½ * 240 = ½ * 2(L + W)

120 = L + W.

Make W the subject of formula

W = 120 - L ---- Equation 1.

The area of a rectangle;

A = L * W

Where A represents the area;

Substitute 120 - L for W in the above formula.

A = (120 - L) * L

A = L(120 - L)

To get an arbitrary value of L, put A = 0

So, we have:

L(120 - L) = 0

L = 0 or 120 - L = 0

L = 0 or L = 120

From the question, we are to calculate the maximum area.

The maximum area is at the mean of the arbitrary value of L

Hence, L = ½(0 + 120)

L = ½(120)

L = 60ft

Recall that W = 120 - L.

So, W = 120 - 60

W = 60ft.

Hence, the dimension of the playground is 60ft by 60ft.

Now, that we have the dimension of the playground, we can now calculate the maximum area.

Area = Length * Width

Area = 60ft * 60ft

Area = 3,600 ft²

Conclusively, the dimension of the playground is 60ft by 60ft and the maximum area of the playground is 3,600ft²

User Teon
by
7.0k points
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