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15x^2+4x-3=0 how to solve using quadratic equation

User Hieu Pham
by
3.4k points

1 Answer

7 votes

Answer:

(3x + 1) (5x - 3)

Explanation:

first multiply 15 by -3 to get -45, then find 2 numbers that multiply to get -45 that also add/subtract to get +4. you will get 5 and -9. Replace the 4 with those numbers and distribute. Find the common factors once you have 2 seperate brackets.

(see photo)

15x^2+4x-3=0 how to solve using quadratic equation-example-1
User Mike Sav
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3.9k points